-booruScraper/util/WebRequest/iri2uri.py

76 lines
2.1 KiB
Python

import urllib.parse
# Convert an IRI to a URI following the rules in RFC 3987
#
# The characters we need to enocde and escape are defined in the spec:
#
# iprivate = %xE000-F8FF / %xF0000-FFFFD / %x100000-10FFFD
# ucschar = %xA0-D7FF / %xF900-FDCF / %xFDF0-FFEF
# / %x10000-1FFFD / %x20000-2FFFD / %x30000-3FFFD
# / %x40000-4FFFD / %x50000-5FFFD / %x60000-6FFFD
# / %x70000-7FFFD / %x80000-8FFFD / %x90000-9FFFD
# / %xA0000-AFFFD / %xB0000-BFFFD / %xC0000-CFFFD
# / %xD0000-DFFFD / %xE1000-EFFFD
escape_range = [
(0xA0, 0xD7FF),
(0xE000, 0xF8FF),
(0xF900, 0xFDCF),
(0xFDF0, 0xFFEF),
(0x10000, 0x1FFFD),
(0x20000, 0x2FFFD),
(0x30000, 0x3FFFD),
(0x40000, 0x4FFFD),
(0x50000, 0x5FFFD),
(0x60000, 0x6FFFD),
(0x70000, 0x7FFFD),
(0x80000, 0x8FFFD),
(0x90000, 0x9FFFD),
(0xA0000, 0xAFFFD),
(0xB0000, 0xBFFFD),
(0xC0000, 0xCFFFD),
(0xD0000, 0xDFFFD),
(0xE1000, 0xEFFFD),
(0xF0000, 0xFFFFD),
(0x100000, 0x10FFFD),
]
def encode(c):
retval = c
i = ord(c)
for low, high in escape_range:
if i < low:
break
if i >= low and i <= high:
retval = "".join(["%%%2X" % o for o in c.encode('utf-8')])
break
return retval
def iri2uri(uri):
"""Convert an IRI to a URI. Note that IRIs must be
passed in a unicode strings. That is, do not utf-8 encode
the IRI before passing it into the function."""
assert uri != None, 'iri2uri must be passed a non-none string!'
original = uri
if isinstance(uri ,str):
(scheme, authority, path, query, fragment) = urllib.parse.urlsplit(uri)
authority = authority.encode('idna').decode('utf-8')
# For each character in 'ucschar' or 'iprivate'
# 1. encode as utf-8
# 2. then %-encode each octet of that utf-8
path = urllib.parse.quote(path)
uri = urllib.parse.urlunsplit((scheme, authority, path, query, fragment))
uri = "".join([encode(c) for c in uri])
# urllib.parse.urlunsplit(urllib.parse.urlsplit({something})
# strips any trailing "?" chars. While this may be legal according to the
# spec, it breaks some services. Therefore, we patch
# the "?" back in if it has been removed.
if original.endswith("?") and not uri.endswith("?"):
uri = uri+"?"
return uri